From: Emil Dotchevski (emil_at_[hidden])
Date: 2008-08-04 21:35:26
On Mon, Aug 4, 2008 at 6:08 PM, Steven Watanabe <watanabesj_at_[hidden]> wrote:
> Emil Dotchevski wrote:
>> On Mon, Aug 4, 2008 at 4:35 PM, Steven Watanabe <watanabesj_at_[hidden]>
>>> It does call operator= when both operands have the same type. Thanks.
>> Is it then true that even foo::operator= throws, in the code below:
>> variant<foo,int> a=foo(....);
>> variant<foo,int> b=foo(....);
>> we will never end up with an int in a?
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