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Subject: Re: [boost] [config] [random] usage of BOOST_NO_MEMBER_TEMPLATE_FRIENDS
From: John Maddock (john_at_[hidden])
Date: 2009-02-07 05:04:10
> Boost.Random uses BOOST_NO_MEMBER_TEMPLATE_FRIENDS to decide
> whether it is safe to define the stream operators.
>
> #if !defined(BOOST_NO_OPERATORS_IN_NAMESPACE) &&
> !defined(BOOST_NO_MEMBER_TEMPLATE_FRIENDS)
> template<class CharT, class Traits>
> friend std::basic_ostream<CharT,Traits>&
> operator<<(std::basic_ostream<CharT,Traits>& os, const uniform_int& ud);
>
> template<class CharT, class Traits>
> friend std::basic_istream<CharT,Traits>&
> operator>>(std::basic_istream<CharT,Traits>& is, uniform_int& ud);
> #endif
>
> However, the documentation of BOOST_NO_MEMBER_TEMPLATE_FRIENDS
> says that BOOST_NO_MEMBER_TEMPLATE_FRIENDS is defined if the compiler
> doesn't support
> template<class P> friend class frd;
>
> It seems from
> https://svn.boost.org/trac/boost/ticket/1068
> that these do not correspond exactly.
I think that's correct.
> Are there any compilers that we still care about,
> that don't support this use of friend?
It looks like VC++ and codegear compilers are the only current compilers we
define this for, so maybe it would be easier to just add a specific
exception for VC++ :
#if !defined(BOOST_NO_OPERATORS_IN_NAMESPACE) &&
!(defined(BOOST_NO_MEMBER_TEMPLATE_FRIENDS) &&
!BOOST_WORKAROUND(BOOST_MSVC, >= 1310))
> Also, it sounds to me like the use of
> BOOST_NO_OPERATORS_IN_NAMESPACE is
> wrong because it is documented as "Compiler requires
> inherited operator friend functions to be defined at namespace scope"
> and there is no inheritance here. Is this right?
Ultimately, it's always best to refer to the test cases for these, in the
case of BOOST_NO_OPERATORS_IN_NAMESPACE it's quite specific to an issue that
the operators library had with operator overload resolution:
https://svn.boost.org/trac/boost/browser/trunk/libs/config/test/boost_no_ops_in_namespace.ipp
So yes it's probably being misused, but I suspect it was added to to fix a
specific issue, and since no current compilers define that macro, I think we
might as well leave it alone for now?
John.
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