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Subject: Re: [boost] [lexical_cast] A suggestion
From: David Abrahams (dave_at_[hidden])
Date: 2009-02-08 17:41:50
on Sun Feb 08 2009, Andrey Semashev <andrey.semashev-AT-gmail.com> wrote:
> David Abrahams wrote:
>> on Sun Feb 08 2009, Ben Muzal <bmuzal-AT-gmail.com> wrote:
>>
>>>> In fact, if we put together all the badly needed functionality that
>>>> overlaps with lexical_cast, and give it appropriate interfaces, I'm not
>>>> entirely convinced that there would be much use for lexical_cast
>>>> anymore.
>>>
>>> Really what is with all of the "slippery slope" arguments?
>>
>> That's not my concern. My concern is that I don't think lexical_cast is
>> a particularly good interface for its main uses, which could be thought
>> of as "to-string" and "from-string."
>
> I disagree. lexical_cast was designed to be simple to use, and I think it does it very
> well. The "to-string" and "from-string" conversions, in their simple form, are just
> corner cases.
Eh? What other uses has it got?!
> If I want to simply parse an int, I don't want to make up a Spirit
> grammar for that or even use scanf.
scanf is *way* lighter weight that lexical_cast.
> I need a C++-style of strtol, which is safe in
> terms of buffer allocation and types.
So write that.
> This is what lexical_cast tries to achieve and it does, to some
> degree. I don't know of any other tools that come this close to this
> goal, neither in Boost, nor outside of it.
So write one (just my opinion). lexical_cast means something very
strange and overly-general, and we should write something targeted at
the real-world uses people actually have.
>>> People are not asking for the kitchen sink. We just want a nothrow
>>> version of the cast and to do that, a default value is needed.
>>
>> I wouldn't say that. boost::optional is another option. In fact, if
>> boost::optional doesn't already provide the exact streaming operator you
>> need, I'd be a little surprised. If it has no streaming operator, we
>> could consider adding the needed one. If it has the wrong streaming
>> operator, it would be pretty easy to invent template nothrow, such that you
>> can write
>>
>> optional<Foo> = lexical_cast<nothrow<Foo> >( something )
>
> I've already expressed myself on this. I just want to add that optional does define
> its streaming operators, and the way they work is no compatible with the goal we're
> trying to achieve with this extension.
Then it's easy enough to define the derived template that *is*
compatible... although as I've said before I don't think lexical_cast is
the right tool for this job anyway.
>>> Lots of times there are cases when a default value simply will not be
>>> acceptable, but quite often one will. Why can't it be easy to support
>>> both models?
>>
>> I just don't think lexical_cast is the interface we need for most
>> convenient string conversions.
>
> Do you have a better interface in mind?
It would take some thought and discussion to perfect, but just off the
top of my head, I'd want something like this:
namespace str
{
template <class T>
struct value
{
operator T() const; // throws iff parse unsuccessful
bool parsed() const; // true iff parse succecssful
...
};
template <class String, class T>
string::value<T>
string::as<T>(String const&);
template <class String, class T>
typename enable_if<is_integral<T>, string::value<T> >::type
string::as<T>(String const&, unsigned base);
template <class T>
std::string
to_str(T const& x);
template <class String, class T>
String
to_str(T const& x);
}
>>> I had not even heard of the <optional> library until reading this
>>> thread. I might update my little boost extension after checking to
>>> see how <optional> affects performance and code bloat -- but really,
>>> <optional> looks rather more complicated than necessary.
>>
>> It has exactly the right semantics, and it tells you more than the
>> version with the default does. With the default, you can't tell whether
>> there was any valid input there or not, because the value represented in
>> the input could be the same as the default.
>
> The point is, often I don't care if the default was actually read from the string or
> taken from the argument.
Yes, but sometimes you will.
-- Dave Abrahams BoostPro Computing http://www.boostpro.com
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