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Subject: Re: [boost] [convert] Default Syntax Idea
From: Stewart, Robert (Robert.Stewart_at_[hidden])
Date: 2009-02-25 09:38:11

On Wednesday, February 25, 2009 9:02 AM
Eric MALENFANT wrote:
> boost-bounces_at_[hidden] wrote:
> > Now I am not so sure. In isolation it looks good:
> >
> > int j = convert_to<int>(s) | 5;
> >
> > What happens when we start mixing with
> >
> > int j = convert_to<int>(s) | 5 >> std::hex;
> > int j = convert_to<int>(s) | 5 >> boost::dothow >> std::hex; or
> > even int j = convert_to<int>(s) >> boost::dothow >>
> std::hex | 5;
> To add to the "I am not sure" side: What if I want to perform a
> bitwise-or on the result of convert_to<int>?

I've just recanted due to operator precedence, though I doubt you'd be very likely to try to use any operator on the result of calling convert().

Rob Stewart robert.stewart_at_[hidden]
Software Engineer, Core Software using std::disclaimer;
Susquehanna International Group, LLP

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