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Subject: Re: [boost] [Bind] How do I get bind to deduce the return type of for_each?
From: Roland Bock (rbock_at_[hidden])
Date: 2010-04-17 07:25:10
Thomas Jordan wrote:
> [snip]
> Thanks for the suggestion, Roland, I am sure you could get something like this to work easily enough. However, if I understand correctly your suggestion involves defining a separate functor - myClass - to take the vocType's, and which I guess wraps the inner call to for_each. I had hoped for a more generic solution which doesn't involve the creation of new functors. I was hoping I could accomplish the objective of passing an algorithm into an algorithm jgenerically, just doing everything at point of call using just Boost.bind, the std::algorithms (wrapped) and using if necessary some boost.function functors to help type deduction. Are we saying this isn't possible?
>
Hi Thomas,
we don't say it isn't possible :-)
Here you go:
// -----------------------------------------------------------
#include <boost/bind.hpp>
#include <boost/bind/protect.hpp>
#include <boost/function.hpp>
#include <vector>
#include <iostream>
using namespace std;
using namespace boost;
int initValue = 0;
class myClass
{
public:
myClass():
mValue(initValue)
{}
myClass(const myClass& rhs):
mValue(initValue++)
{
}
void func()
{
cout << mValue << endl;
}
private:
int mValue;
};
typedef vector<myClass> vocType;
typedef vector<vocType> vovType;
int main()
{
vovType vov(10, vocType(10, myClass()));
for_each(vov.begin(), vov.end(),
bind(for_each< vocType::iterator, function<void (myClass&)> >,
bind<vocType::iterator>(&vocType::begin, _1),
bind<vocType::iterator>(&vocType::end, _1),
protect(bind(&myClass::func, _1))
)
);
}
// -----------------------------------------------------------
Please let me know if this is working for you.
Regards,
Roland
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