Subject: Re: [boost] [move] Reason for BOOST_COPY_ASSIGN_REF?
From: Stewart, Robert (Robert.Stewart_at_[hidden])
Date: 2010-04-21 07:22:46
Chad Nelson wrote:
> - - How is the "copy assignment operator" different from the normal
> operator=(const T&)?
The "normal operator=(const T&)" *is* the copy assignment operator. That's always been the name of that member function. There can be any number of assignment operators, providing interoperability with other types, but there's only one that is expected to assign from another instance of the same class to make *this a copy of the source.
With C++0x, there is also a _move assignment operator_, which uses an rvalue reference.
Precision in terminology, especially as the variations increase, is helpful.
Rob Stewart robert.stewart_at_[hidden]
Software Engineer, Core Software using std::disclaimer;
Susquehanna International Group, LLP http://www.sig.com
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