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Subject: Re: [boost] Does boost help in creating generic function wrappers?
From: Andy Venikov (avenikov_at_[hidden])
Date: 2010-07-15 15:56:37

Steven Watanabe wrote:

>> Correct me if I'm wrong, but I think it's not going to work when the
>> inner functor has (T const &) parameter. If my wrapper declares
>> everything T &, then it won't be able to accept non-const rvalues
>> whereas the original functor was able to do that.
> If you use forward_adapter, you don't need to handle non-const rvalues.
> forward_adapter handles the overloading and passes const or non-const
> lvalues to your function object.

I don't think I follow.

Let's say that you have a functor f of type F, where it's
legal to call it like this:

int n = 5;
f(n, 10); //compiles fine
f(n, n); /compiles fine

You seem to suggest I create my own my_wrapper<F> and define an
operator() with only references:

template <typename Func>
class my_wrapper
....//ignore the problem of generating multiple operator()'s
     //for different Func arity

template <typename T1, typename T2>
/*deduce ret type*/
operator() (T1 & in1, T2 & in2)
   //Do something useful here

   return func_(in1, in2);


... and then wrap it in a forward_adapter:

template <typename Func>
forward_adapter<my_wrapper<Func> > wrap(Func const & in)
   return forward_adapter<my_wrapper<Func> >(my_wrapper<Func>(in));

But now this fails to compile:

wrap(f)(n, 10); //Fails, because 10 is passed as int const &

whereas this used to compile fine:
f(n, 10);

What am I missing?


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