Subject: Re: [boost] [function] function wrapping with no exception safetyguarantee
From: Emil Dotchevski (emil_at_[hidden])
Date: 2010-10-13 13:31:04
On Wed, Oct 13, 2010 at 9:41 AM, Daniel Walker
> In "promoting" function pointers to function objects, boost::function
> must transfer the call precondition from function pointers. To do this
> in an exception safe way, it must check whether the call precondition
> is met, otherwise it cannot offer a strong exception safety guarantee
> during the execution of boost::function::operator().
What Peter said: your terminology is wrong.
Operator() of boost::function has basic (not strong) exception safety
guarantee and this is true regardless of whether it wraps a function
pointer or another callable object.
Basic exception safety guarantee means that *if* an exception is
emitted as a result of calling boost::function::operator(), the state
of the program may be altered but no resources will leak. Whether or
not an exception is emitted has nothing to do with exception safety.
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