Re: [boost] review request: addition to type_traits library ofhas_operator_xxx

Subject: Re: [boost] review request: addition to type_traits library ofhas_operator_xxx
From: John Maddock (boost.regex_at_[hidden])
Date: 2010-12-10 04:04:30

>1. is there an easy way to get the type of an expression and to pass
>it to is_convertible

Not in C++03, only in C++0x

>2. if not, why not just using the working code I wrote already?

That sounds sensible - I may have misunderstood here - I thought from the 
comments I saw that you had written your own is_convertible version, but 
rather it looks like you have some implementation details (functions) that 
just happen to have a similar name?  If so I suggest you leave it as it is - 
sorry for the confusion on that one!

John.