Re: [boost] [typeof] deducing type at class level

Subject: Re: [boost] [typeof] deducing type at class level
From: Vicente Botet (vicente.botet_at_[hidden])
Date: 2011-06-22 13:04:02

Mathias Gaunard-2 wrote:
> 
> On 22/06/2011 18:02, lcaminiti wrote:
>> Hello all,
>>
>> Is there any way to use BOOST_TYPEOF at class level? For example:
>>
>> struct vect {
>>      size_t size();
>>
>>      typedef BOOST_TYPEOF(size()) size_type; // can I make this work
>> somehow?
> 
> typedef BOOST_TYPEOF(make<vect>().size()) size_type;
> 
> with
> 
> #ifndef BOOST_NO_RVALUE_REFERENCES
> 
> template<class T>
> typename enable_if<
>     is_reference<T>,
>     T
>  >::type
> make();
> 
> template<class T>
> typename disable_if<
>     is_reference<T>,
>     T&
>  >::type
> make();
> 
> #else
> 
> T&& make();
> 
> #endif
> 
> 

Hi,

note that there is already declval in the standard ans in Boost.Utility taht
can be used instead of make.

20.2.4	Function template declval [declval]
1	The library provides the function template declval to simplify the
definition of expressions which occur as unevaluated operands (Clause 5).

Best,
Vicente

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