Subject: Re: [boost] [typeof] deducing type at class level
From: Steven Watanabe (watanabesj_at_[hidden])
Date: 2011-06-22 16:08:02
On 06/22/2011 12:40 PM, Jeffrey Lee Hellrung, Jr. wrote:
> On Wed, Jun 22, 2011 at 10:00 AM, Mathias Gaunard <
> mathias.gaunard_at_[hidden]> wrote:
>> On 22/06/2011 18:42, Jeroen Habraken wrote:
>> This can be done using boost::type_traits::add_**reference I believe:
>>> template<class T>
>>> typename add_reference<T>::type make();
>> Actually there is a declval somewhere in boost that more or less does this,
>> unfortunately it returns by value in C++03, which is a big no-no for me,
>> since it restricts it to copyable types.
> [At the risk of drifting off-topic...] If you're worried about that,
> shouldn't you be using declval<T&>() if you really want an lvalue?
Yeah. Returning by value is the only way
to get an rvalue in C++03.