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Subject: Re: [boost] [proto] Can't use functions in expressions?
From: John Maddock (boost.regex_at_[hidden])
Date: 2011-09-01 13:05:27

>> BTW I couldn't find any examples of using proto::function in a grammar,
>> it
>> wasn't obvious to me what it's template arguments should be, or indeed
>> whether this actually enabled the function call operator rather than my
>> use
>> case?
> Just keep in mind, that proto::function is a expression that can have
> variadic
> children. The first is the function expression, and the remaining the
> function
> arguments. proto::vararg might help here.

Got it, this needs to be documented under
though, and an example wouldn't harm either ;-)


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