Re: [boost] [local] Any "active Boost library author" in favor of Boost.Local?

Subject: Re: [boost] [local] Any "active Boost library author" in favor of Boost.Local?
From: Mathias Gaunard (mathias.gaunard_at_[hidden])
Date: 2011-11-25 14:03:20

On 11/25/2011 06:44 PM, Lorenzo Caminiti wrote:

> On the contrary such a feature is not supported by the Phoenix
> solution *AFAIK* precisely because the functor is not local to the
> outer class (whereas the Local functor is local to the enclosing
> member function and therefore to the outer class). For example:
>
> #include<boost/phoenix/core.hpp>
> #include<boost/phoenix/function.hpp>
> #include<iostream>
>
> namespace impl
> {
>      template<typename This>
>      void f(This this_)
>      {
>          this_->publ();
>          // this_->prot(); // error :(
>          // this_->priv(); // error :(
>      }
> }
>
> BOOST_PHOENIX_ADAPT_FUNCTION(void, globalf, impl::f, 1)
>
> struct x {
>      void f() {
>          globalf(this)();
>      }
>
> public:
>      void publ() { std::cout<<  "public"<<  std::endl; }
> protected:
>      void prot() { std::cout<<  "protected"<<  std::endl; }
> private:
>      void priv() { std::cout<<  "private"<<  std::endl; }
> };
>
> int main ( ) {
>      x xx;
>      xx.f();
>      return 0;
> }
>
> DISCLAIMER: I apologize in advance if there's a way to do access priv
> and prot from the Phoenix global functor which I was not able to find.
> I'm sure Phoenix experts will be able to correct my example if such a
> possibility exists :)

It's not possible with Phoenix, though I believe there are hacks to make 
it possible somewhat.

In any case I don't think this is even Phoenix code. There is no real 
phoenix expression involved, it's just a function being adapted into a 
function object.