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Subject: Re: [boost] [optional] generates unnessesary code for trivial types
From: Andrzej Krzemienski (akrzemi1_at_[hidden])
Date: 2012-02-10 03:10:10
> > int i = 1;
> > int j = 2;
> > optional<int&> oi = i;
> > optional<int&> oj = j;
> > i = j;
> > The effect here is that i remains 1, j remains 2 and oi and oj both
hold a
> > reference to j. You may find it less surprising but if you think of
> > optional reference as a regular reference that is initialized a bit
later,
> > the behavior is not what you would expect.
>
> Huh? How does oi come to hold a reference to j?
Apologies, I meant to say
int i = 1;
int j = 2;
optional<int&> oi = i;
optional<int&> oj = j;
oi = oj;
Boost.Optional documentation explains it better:
http://www.boost.org/doc/libs/1_48_0/libs/optional/doc/html/boost_optional/rebinding_semantics_for_assignment_of_optional_references.html
Regards,
&rzej
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