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Subject: Re: [boost] has_member_fnc?
From: Stewart, Robert (Robert.Stewart_at_[hidden])
Date: 2012-03-16 14:29:44

Olaf van der Spek wrote:
> On Fri, Mar 16, 2012 at 4:07 PM, Stewart, Robert
> <Robert.Stewart_at_[hidden]> wrote:
> > Neal Becker wrote:
> >>
> >> It seems c++11 has a new way to spell enable_if, and this
> >> can be used to implement has_member_fnc, as in this example:
> >>
> >>
> >
> > I wish I could see the code, but pastebin is blocked here.
> //Special template for EE_PDUs, which are weird
> template <typename T>
> auto getKey_imp(const T &struc, int &key, int) ->
> //If struc has an interesting_member member, this
> //version is used
> decltype(struc.interesting_member, void())
> {
> key = 0;
> }
> template <typename T>
> void getKey_imp(const T &struc, int &key, long)
> //struc didn't have an interesting_member member, do
> //nothing
> {
> }
> public:
> template <typename T>
> bool getKey(const T &struc, int &key)
> {
> getKey_imp(struc, key, 0);
> return key == 0; //Successful?
> }

Thank you.

Did I miss something? That just tests for a member by name. To test for a member function, you'd need to specify the signature to make it worthwhile.

Rob Stewart robert.stewart_at_[hidden]
Software Engineer using std::disclaimer;
Dev Tools & Components
Susquehanna International Group, LLP


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