Re: [boost] [coroutine] Experimenting with interfaces

Subject: Re: [boost] [coroutine] Experimenting with interfaces
From: Oliver Kowalke (oliver.kowalke_at_[hidden])
Date: 2012-09-21 13:34:12

Am 21.09.2012 19:17, schrieb Eugene Yakubovich:
>
> template <typename C>
> void timer(C c, chrono::seconds interval) {
>      while( interval != chrono::seconds::zero() ) {
>          this_thread::sleep_for(interval);
>          interval = c(interval);
>      }
> }
>
> chrono::seconds tick(chrono::seconds last_interval) {
>      std::cout << "tick" << std::endl;
>      return last_interval;
> }
>
> // use with function
> timer(tick, chrono::seconds(1));
>
> // use with coroutine
> coroutine<chrono::seconds(chrono::seconds)> c(
>      [](coroutine<chrono::seconds(chrono::seconds)> c, chrono::seconds i) {
>          timer(c, i);
>      }
> );
>
> chrono::seconds s = c(chrono::seconds(1));
> s = c(2*s);
> s = c(3*s);
> s = c(5*s);
>
>
> I'm not sure what this means for the best interface but I did want to
> share these thoughts and examples.
thank you for your examples:
If coroutine's template signature returns a type different from void it 
is required that the coroutine function does return the same type 
instead of void as in your example.

template <typename C>
void timer(C c, chrono::seconds interval) {
   //  while( interval != chrono::seconds::zero() ) {
   //      this_thread::sleep_for(interval);
   //      interval = c(interval);
   //  }
}

coroutine<chrono::seconds(chrono::seconds)> c(
     [](coroutine<chrono::seconds(chrono::seconds)> c, chrono::seconds i) {
         timer(c, i);
     }
);

chrono::seconds s = c(chrono::seconds(1));

Which value has variable 's' after return from 'c(chrono::seconds(1))' ?

regards,
Oliver