[boost] [lexical_cast] cast of int8_t

Subject: [boost] [lexical_cast] cast of int8_t
From: Jochen Wilhelmy (jochen.wilhelmy_at_[hidden])
Date: 2012-10-13 16:35:48

Hi!
In a previous message I asked if lexical_cast could throw 
boost::numeric::positive_overflow when the parsing is ok but the value 
too large for the target type. this turned out to be difficult because 
it breaks existing code, alternatively there could be another exception 
derived from bad_lexical_cast that indicates the overflow but this seems 
to be a lot of work.

another question is why does lexical_cast treat int8_t and uint8_t like 
char? technically I see no reason for this as c++ has three types: char, 
signed char and unsigned char. in my code I use only char for characters 
and signed/unsigned char as numbers. I know that the standard stream 
operator << treats signed/unsigned char as char but I know no 
explanation for this (I consider it a bug ;-)

-Jochen