# Boost :

Subject: Re: [boost] boost interval arithmetic
From: ÐŸÐ°Ð²ÐµÐ» ÐšÑƒÐ´Ð°Ð½ (coodan_at_[hidden])
Date: 2015-01-15 07:45:18

Thu, 15 Jan 2015 13:16:19 +0100 Ð¾Ñ‚ "Thijs (M.A.) van den Berg" <thijs_at_[hidden]>:
>
>> OK, but that is enough to conclude that [-inf, inf] IS( [-inf, -1] U [1, inf]) is not true and this operator returns not correct result, no matter is the way it corrupts own result documented or not.
>>
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>No, you are wrong here again, you claim so much but demonstrate nothing. You seem to lack the ability to reason precisely and mix up set theory with numerical interval computations.
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>You should stick to pen and paper math, learn about logical inference
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>(A and NOT(A))->proves the earth is flat
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>Â ,lean about numerical representation theory (like floats) and don't touch a computer or post in forums until you do that!
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>What in your opinion is the value of "d" in the following statement?
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>
>double d=1/3;
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>
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I would like you say me first that you really think that [-inf, inf] IS EMPTY, as I asked first.

But, still, OK, double d=1/3 will contain a result of int operator/ as values you are dividing are int. So what? Next question you will ask will be a result ofÂ  'double d=1%3;' ???!