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Subject: Re: [boost] boost interval arithmetic
From: Thijs van den Berg (thijs_at_[hidden])
Date: 2015-01-15 09:30:58

> If not certain result is good, you must also be ready to accept [-inf,
> inf] as a result of 2 + 2 operation.
> No, that's not what boost interval does.
You are constructing invalid hypothetical cases,"what is boost said
2+2=[-inf,inf]?". Like said before, you can infere any logical conclusion
bases on invalid precondition. (inconsistent clause) -> (any statement)

 What *would* boost interval do in case of 2+2,.... and is that correct or

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