Subject: Re: [boost] [metaparse] performance comparisons?
From: Peter Dimov (lists_at_[hidden])
Date: 2015-06-02 08:59:43
Louis Dionne wrote:
> > I assume that you mean for 'f' to be constexpr?
> No, it does not change a thing. It was on purpose that I did _not_ make it
> constexpr, in order not to mix concerns. What we're interested in is the
> constexpr-ness of `s` within the body of `f`, whether `f` is constexpr or
> not does not change anything.
I know that it doesn't, but we're demonstrating that 's' isn't constexpr
even when 'f' is, which is a stronger claim than that 's' isn't constexpr
when 'f' isn't. :-)
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