Re: [boost] [Config] Support for switching between std::andboost::equivalents.

Subject: Re: [boost] [Config] Support for switching between std::andboost::equivalents.
From: Peter Dimov (lists_at_[hidden])
Date: 2015-06-07 06:41:32

Edward Diener wrote:
> I design a library which, let's say, takes a regex object as parameter to 
> some exported function. If the end-user of my library is compiling in 
> C++11 mode is it more likely that his use of regex will be std::regex or 
> boost::regex ? IMO it is the former. Conversely if the end-user of my 
> library is compiling in C++03 mode is it more likely that his use of regex 
> will be std::regex or boost::regex ? That's a loaded question of course 
> because std::regex won't be available to him if he compiles in C++03 mode. 
> So my preferred usage of regex in my library, all else being equal, is to 
> use boost::regex in C++03 mode and std::regex in C++11 mode.

This makes sense, and the question of dependencies and modular distributions 
is actually a side show.

But you do realize that you'll be breaking your customer's C++03 (presumably 
tried and tested) code the moment he adds -std=c++11 in order to use a 
for(:) loop, right?