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Subject: Re: [boost] [iterator] function_output_iterator constructed from a lambda function is not assignable
From: Peter Dimov (lists_at_[hidden])
Date: 2016-02-14 22:17:35
Paul Fultz II wrote:
> One way to deal with this is to put it into boost::optional.
boost::optional<T> uses T::operator= when the source and the target hold a
value.
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