Boost logo

Boost :

From: Peter Dimov (pdimov_at_[hidden])
Date: 2020-09-25 14:47:04


Andrzej Krzemienski wrote:

> My understanding of a "vocabulary type" is that it should be usable (not
> necessarily with maximum efficiency) for *any* usage.

This is not at all what a vocabulary type is. A vocabulary type is a type
via which two libraries can communicate, without that type being defined by
either of them. E.g. std::size_t is a vocabulary type. It's obviously not
usable for *any* usage.


Boost list run by bdawes at acm.org, gregod at cs.rpi.edu, cpdaniel at pacbell.net, john at johnmaddock.co.uk