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From: Claudio DeSouza (cdesouza_at_[hidden])
Date: 2024-12-04 14:41:38
I tend to disagree. In my opinion even this:
hash.update( as_bytes( span{st} ) );
Is better than this:
hash.update( v.data(), v.size() );
Something like as_byte_span is just an extra nicety, but I think it is easy
to underestimate how you can avoid mistakes with the first example as
opposed to the second.
On Wed, Dec 4, 2024 at 2:38â¯PM Peter Dimov via Boost <boost_at_[hidden]>
wrote:
> Claudio DeSouza wrote:
> > > So I switched `update` back to void const*. The "type safety" gains
> > > aren't worth the substantial decrease in usability.
> > >
> >
> > In my experience, the usability/readability gains are on the side of
> using span.
> > This may involve providing extensions, but at the end of the day you get
> more
> > C++-friendly constructs.
>
> Well... no, they aren't.
>
> Suppose you have the data in `std::vector<unsigned char> v`. With the
> current
> `update` that's
>
> hash.update( v.data(), v.size() );
>
> And if you have the data in `std::string st`, that's
>
> hash.update( st.data(), st.size() );
>
> Now suppose `update` takes `span<unsigned char const>`. For `v`, this is
>
> hash.update( v );
>
> which is nice; but for `st`, that would be (assuming C++17)
>
> hash.update( as_bytes( span{st} ) );
>
> which is not so nice.
>
> In Chromium you have as_byte_span, which does as_bytes(span(x)), so
> it'd be better.
>
>
>
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