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Ublas : |
From: Sebastian Gesemann (s.gesemann_at_[hidden])
Date: 2008-01-26 06:06:34
> Actualy you need about 2^(7*5+2) doubles for a 127^5 x 5 matrix. So
> you need to use 64 bit integers for addressing the matrix' entries.
> Also 2^(7*5+2) doubles make 2^(7*5+2+3) bytes which is about 128 Gigs.
> Am I wrong?
Sorry, this is wrong, I forgot the 3:
127^5 * 5 doubles need
2^(log2(127)*5 + log2(5 columns) + log2(8 bytes/double)) bytes = 1.2 Tera Bytes
Cheers!
SG