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Ublas : |
Subject: Re: [ublas] returning a ublas matrix from a function
From: sanann (padalasaisandeep_at_[hidden])
Date: 2014-08-05 07:24:30
Thank you. I am just a beginner, i am more used to matlab due to which i get
confused quite quickly. However i slowly came over the problem. but i now
face a new problem if possible for you can explain with a little patience it
would be of great help.
#include <boost/numeric/ublas/matrix.hpp>
#include <boost/numeric/ublas/io.hpp>
using namespace boost;
using namespace boost::numeric::ublas;
typedef boost::numeric::ublas::matrix<double> BMT;
BMT fun(int w,int h)
{
BMT M[3]=
{
boost::numeric::ublas::scalar_matrix<double>(w, h),
boost::numeric::ublas::scalar_matrix<double>(w, h),
boost::numeric::ublas::scalar_matrix<double>(w, h)
};
return M[2];
}
int main()
{
unsigned w,h;
w = 2;
h = 2;
boost::numeric::ublas::scalar_matrix<double> Z[3];
Z[3]=fun(w,h);
std::cout<<fun<<std::endl;
return 0;
}
and I end up with error: no match for 'operator=' (operand types are
'boost::numeric::ublas::scalar_matrix<double>' and 'BMT {aka
boost::numeric::ublas::matrix<double>}')
Z[3]=fun(w,h);
^
is my approach correct or have I misunderstood something?
thanks in advance
-- View this message in context: http://boost.2283326.n4.nabble.com/returning-a-ublas-matrix-from-a-function-tp4666050p4666061.html Sent from the Boost - uBLAS mailing list archive at Nabble.com.