[Boost-users] Tokenizer: how to eliminate unwanted null tokens?

31 Oct 2005

      Hi!

The following code uses '\0' and ';' as seperators and produces the
result:

<X><Y><><Z><>

string str=string("X;Y\0\0Z\0",7);
typedef tokenizer<boost::escaped_list_separator<char> > Tok;
escaped_list_separator<char> sep(string(),string("\0;",2),string());
Tok tokens(str, sep);
for(Tok::iterator i = tokens.begin();i != tokens.end();++i)
  cout << "<" << *i << ">";

How to revise it in order to get this result?

<X><Y><Z>

Thank you in advance!

CN

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