Just a small addition to my example: I was unsure if compiler will deduce the type of the function param without explicit template specialization. At least MSVC 8 did it. Hope this is so by C++ standard. Here is the example: include <iostream> template<class T> void function_template(T value) { std::cout << value << std::endl; } template<class T> void other_function_template(T value) { std::cout << value*value << std::endl; } struct function_template_wrapper { template<class T, void(*Fct)(T)> static inline void call(T value) { Fct(value); } }; int main(int argc, char* argv[]) { function_template_wrapper::call<int, function_template>(10); function_template_wrapper::call<int, other_function_template>(10); return 0; } With Kind Regards, Ovanes