Igor R wrote:
template<class String, class Traits> class basic_vpath; typedef basic_vpath< std::string, path_traits> vpath;
template<class String, class Traits> class basic_vpath :public basic_path< String, Traits> { };
But I don't understand why I can just fine: CString strUserDirectory= _T("C:\\cpp\\RA_User_2_2\\$(TEST)"); path aPath( strUserDirectory );
But can't convert from CString, or even std::string with:
CString strUserDirectory= _T("C:\\cpp\\RA_User_2_2\\$(TEST)"); vpath aPath( strUserDirectory );
Does vpath class have a constructor that takes CString or LPTCSTR?
Hi, From what I see, basic_path will with < std::string, path_traits > ( from path.hpp). I'm deriving from basic_path and using that constructor. This line 'looks' to work fine for path: typedef basic_path< std::string, path_traits > path; But I get the error: 'basic_vpath<String,Traits>::basic_vpath(const basic_vpath<String,Traits> &)' : cannot convert parameter 1 from 'CString' to 'const basic_vpath<String,Traits> &' When I add my extension above. I'd like this vpath class to have all the functionallity of path. The added stuff would kick in on a signature of $(..) in the path. Best, Dan. .