Mojmir Svoboda <mojmir.svoboda <at> logicacmg.com> writes: I was intrigued by this problem, but I couldn't solve it myself. I think it has to do with the tuple (user defined types, overloaded operator<<, Bll). consider: typedef int value_t; typedef std::vector<value_t> vect_t; typedef std::pair<value_t, value_t> value_t_pair; typedef std::vector<value_t_pair> vect2_t; value_t make_value_t (value_t v) { return v; } value_t_pair make_value_t_pair(value_t v) { return std::make_pair(v, v); } std::ostream& operator<<(std::ostream& ros, const value_t_pair&) { return ros; } void Foo() { vect_t vec; //compiles std::for_each(vec.begin, vec.end(), std::cout << boost::lambda::bind(&make_value_t, boost::lambda::_1)); //does not compile std::for_each(vec.begin, vec.end(), std::cout << boost::lambda::bind(&make_value_t_pair, boost::lambda::_1)); //does also not compile std::for_each(vec.begin, vec.end(), std::cout << boost::lambda::bind<value_t_pair> (&make_value_t_pair, boost::lambda::_1)); } But maybe a Bll guru can give a better answer.