Greetings, I would like to crate a lambda expression that simply executes two functions sequentially. I have: using namespace boost; using namespace boost::lambda; function0<void> func1 = cout << constant('1'); function0<void> func2 = cout << constant('2'); I have tried: function0<void> funcs = (func1, func2); but this seems to execute only one of the two functions when it is called. I have also tried: function0<void> funcs = (_1(), _2())(func1, func2); but my compiler (GCC 3.3 under darwin) barfs it up, with error messages: ---------- main.cpp: In function `int main(int, char**)': main.cpp:58: error: no match for call to `(boost::tuples::null_type) ( boost::function0<void, std::allocator<boost::function_base> >&, boost::function0<void, std::allocator<boost::function_base> >&)' /usr/local/include/boost-1_31/boost/lambda/detail/lambda_functors.hpp: In member function `RET boost::lambda::placeholder<1>::call(A&, B&, C&, Env&) const [with RET = boost::tuples::null_type, A = const boost::tuples::null_type, B = const boost::tuples::null_type, C = const boost::tuples::null_type, Env = const boost::tuples::null_type]': /usr/local/include/boost-1_31/boost/lambda/detail/lambda_functors.hpp:143: instantiated from `typename T::sig<boost::tuples::null_type>::type boost::lambda::lambda_functor<Base>::operator()() const [with T = boost::lambda::placeholder<1>]' main.cpp:58: instantiated from here /usr/local/include/boost-1_31/boost/lambda/detail/lambda_functors.hpp:65: error: invalid application of `sizeof' to an incomplete type ---------- (line 58 is the assignment to funcs) I'd appreciate any advice :) -Gabe Redner