On Thu, May 19, 2011 at 5:24 PM, Sebastian Redl < sebastian.redl@getdesigned.at> wrote:

On 19.05.2011, at 08:56, Robert Jones wrote:

Hi All

Is it possible and practical to use the put and get methods of Boost.PropertyTree with std algorithms?

I've written this snippet, which doesn't compile, which I think is because I have not correctly expressed the return type of "put()". Is it possible to do this?

Yes, the put() overloads all return the affected tree node.

for_each( boost::begin( v ), boost::end( v ), bind( static_cast<void (ptree::*)( const std::string &, unsigned )>( & ptree::put ), boost::ref( tree ), "Values.value", _1 ) );

Try this:

static_cast<ptree& (ptree::*)(...)>

Hi Sebstian Thanks for that, I thought that should work too, but seems there's still an overload problem! #include <algorithm> #include <vector> #include <boost/range.hpp> #include <boost/bind.hpp> #include <boost/property_tree/ptree.hpp> int main( ) { using boost::property_tree::ptree; std::vector<unsigned> v; ptree tree; ptree & ( ptree::*myput )( const std::string &, unsigned ) = & ptree::put; for_each( boost::begin( v ), boost::end( v ), bind( myput, boost::ref( tree ), "Values.value", _1 ) ); }

g++ ptree.cpp

ptree.cpp: In function ‘int main()’: ptree.cpp:14: error: no matches converting function ‘put’ to type ‘struct boost::property_tree::ptree& (struct boost::property_tree::basic_ptree<std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::less<std::basic_string<char, std::char_traits<char>, std::allocator<char> > > >::*)(const struct std::string&, unsigned int)’ /usr/include/boost/property_tree/ptree.hpp:446: error: candidates are: template<class Type, class Translator> boost::property_tree::basic_ptree<K, D, C>& boost::property_tree::basic_ptree::put(const typename boost::property_tree::path_of<Key>::type&, const Type&, Translator) [with Type = Type, Translator = Translator, Key = std::basic_string<char, std::char_traits<char>, std::allocator<char> >, Data = std::basic_string<char, std::char_traits<char>, std::allocator<char> >, KeyCompare = std::less<std::basic_string<char, std::char_traits<char>, std::allocator<char> > >] /usr/include/boost/property_tree/ptree.hpp:455: error: template<class Type> boost::property_tree::basic_ptree<K, D, C>& boost::property_tree::basic_ptree::put(const typename boost::property_tree::path_of<Key>::type&, const Type&) [with Type = Type, Key = std::basic_string<char, std::char_traits<char>, std::allocator<char>

, Data = std::basic_string<char, std::char_traits<char>, std::allocator<char> >, KeyCompare = std::less<std::basic_string<char, std::char_traits<char>, std::allocator<char> > >]

Any ideas? Thx - Rob.

On Thu, May 19, 2011 at 6:00 PM, Sebastian Redl < sebastian.redl@getdesigned.at> wrote:

On 19.05.2011, at 10:52, Robert Jones wrote:

On Thu, May 19, 2011 at 5:24 PM, Sebastian Redl < sebastian.redl@getdesigned.at> wrote:

...

On 19.05.2011, at 08:56, Robert Jones wrote:

Hi All

Is it possible and practical to use the put and get methods of Boost.PropertyTree with std algorithms?

I've written this snippet, which doesn't compile, which I think is because I have not correctly expressed the return type of "put()". Is it possible to do this?

Yes, the put() overloads all return the affected tree node.

for_each( boost::begin( v ), boost::end( v ), bind( static_cast<void (ptree::*)( const std::string &, unsigned )>( & ptree::put ), boost::ref( tree ), "Values.value", _1 ) );

Try this:

static_cast<ptree& (ptree::*)(...)>

Hi Sebstian

Thanks for that, I thought that should work too, but seems there's still an overload problem!

#include <algorithm> #include <vector> #include <boost/range.hpp> #include <boost/bind.hpp> #include <boost/property_tree/ptree.hpp>

int main( ) { using boost::property_tree::ptree;

std::vector<unsigned> v; ptree tree;

ptree & ( ptree::*myput )( const std::string &, unsigned ) = & ptree::put;

The first argument should be a ptree::path_type (= string_path<char>), not std::string.

Hi Sebastian YES! At last, it works. I had to change the last parameter to a const reference too, but your strategy of correctly matching the exact signature is the way to go. Final code... int main( ) { using boost::property_tree::ptree; std::vector<unsigned> v; ptree tree; ptree & ( ptree::*myput )( const ptree::path_type &, const unsigned & ) = & ptree::put; for_each( boost::begin( v ), boost::end( v ), bind( myput, boost::ref( tree ), "Values.value", _1 ) ); } Many Thanks - Rob.