Peter Dimov wrote:

Michael Marcin:

...

Let's say I have a std::list of a functor with a member function

virtual operator()( int, int )

Is there an easy way to call each function in this list using for_each?

Intuitively I'd expect to be able to do something like:

void call_each( std::list<functor>& l ) { std::for_each( l.begin(), l.end(), boost::bind(_1,5,20) ); }

With boost::bind, which doesn't evaluate its first argument, you'll need to use apply<>, as explained in

http://www.boost.org/doc/libs/1_36_0/libs/bind/bind.html#nested_binds

Ah I knew it would be obvious. Missed that thanks! -- Michael Marcin

Robert Jones:

On Thu, Oct 16, 2008 at 11:12 PM, Peter Dimov <pdimov@pdimov.com> wrote:

...

With boost::bind, which doesn't evaluate its first argument, you'll need to use apply<>, as explained in

http://www.boost.org/doc/libs/1_36_0/libs/bind/bind.html#nested_binds

I understand the "how" of that, but not the "why". Why does bind not evaluate if first argument?

With apologies for the late response: The first argument is not evaluated because this is what's needed most often. It's common to use bind as an implementation detail as in template<class F> void g1( F f ) { g2( boost::bind( f, _2, _1 ) ); } and, since the caller of g1 may well pass boost::bind(...) to it, evaluating f would mean more boost::protect's. The evaluation of the first argument is practically only needed for cases of the form bind( _1, _2 ). We could have made it so that placeholders are evaluated, but nested binds are not; this would cover nearly all use cases. The reason for not doing that in boost::bind is technical (and somewhat historical): the object returned by boost::bind always has a fixed result_type, and bind( _1, _2 ) cannot have one. There is no technical reason that prevents bind<R>( _1, _2 ) from being handled, though. I just missed this possibility, and nobody has suggested it (to the best of my knowledge). -- Peter Dimov http://www.pdplayer.com