23 Jan
2015
23 Jan
'15
9:05 p.m.
According to the standard, the type of the object yielded by a lambda expression has an implicitly declared default constructor/copy constructor/destructor
I believe that a lambda never has a default constructor even for stateless lambdas.(Even though, it should). Paul -- View this message in context: http://boost.2283326.n4.nabble.com/RFC-Expression-Validity-Asserts-tp4671480... Sent from the Boost - Dev mailing list archive at Nabble.com.