Subject: [Boost-bugs] [Boost C++ Libraries] #2556: Perl regex replacement
From: Boost C++ Libraries (noreply_at_[hidden])
Date: 2008-12-01 16:33:44
#2556: Perl regex replacement
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Reporter: jcombe_at_[hidden] | Owner: johnmaddock
Type: Bugs | Status: new
Milestone: Boost 1.38.0 | Component: regex
Version: Boost 1.37.0 | Severity: Problem
Keywords: |
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I have code that reads a lookup table from memory and then attempts to
search for the word found in the lookup table in some data using a regular
expression:-
(.*\b)word(\b.*)
Where this matches I call replace with the following
$1WORD$2
This falls down when the word is "2lt" as I get the following to search
for
(.*\b)2lt(\b.*)
With replacement
$12LT$2
What happens is it sees $12 as the substring to replace and since I only
have two pairs of brackets in my regular expression $12 does not exist and
so in effect the 2 in my input data is lost.
I am using Perl format regular expressions (boost::regex::perl)
In Perl I can resolve this by making the replacement
${1}2LT${2}
When I do this using boost I get the literal text as above output
(including ${1} etc.) not the text that I expect. Since I've told Boost to
use Perl syntax I would expect a regular expression replacement in Perl
and Boost to behave the same way.
Is this a bug ?
Thanks
Jon
-- Ticket URL: <https://svn.boost.org/trac/boost/ticket/2556> Boost C++ Libraries <http://www.boost.org/> Boost provides free peer-reviewed portable C++ source libraries.
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