Re: [Boost-bugs] [Boost C++ Libraries] #3628: condition.notify_one() does not wake up a thread that is in condition.wait() or condition.timed_wait()

Subject: Re: [Boost-bugs] [Boost C++ Libraries] #3628: condition.notify_one() does not wake up a thread that is in condition.wait() or condition.timed_wait()
From: Boost C++ Libraries (noreply_at_[hidden])
Date: 2009-11-26 14:36:50


#3628: condition.notify_one() does not wake up a thread that is in
condition.wait() or condition.timed_wait()
--------------------------------------------------+-------------------------
 Reporter: Shouaib Ahmed <ranashoaib@…> | Owner: anthonyw
     Type: Bugs | Status: new
Milestone: Boost 1.41.0 | Component: thread
  Version: Boost 1.40.0 | Severity: Problem
 Keywords: condition |
--------------------------------------------------+-------------------------

Comment(by Shouaib Ahmed <ranashoaib@…>):

 Replying to [comment:2 viboes]:
> Replying to [ticket:3628 Shouaib Ahmed <ranashoaib@…>]:
> > You can see in the attached project's TestBoostThread.cpp file that in
 ThreadFuncWaiter(), the thread is in timed_wait() call before it releases
 the mutex to let the ThreadFuncNotifier() thread notify it. But inside
 notify_one(), most of the time it will choose not to notify any "waiter".
 The total_count class member is 0 when that happens. If I uncomment the
 three lines marked as WORKAROUND_ in TestBoostThread.cpp, then the threads
 will be notified, but this is just a workaround.
>
> Have you tried to protect with a mutex the theConditions variable? This
 variable is used by ThreadFuncNotifier() and ThreadFuncWaiter().

 It is protected by a mutex. May be you overlooked that.

-- 
Ticket URL: <https://svn.boost.org/trac/boost/ticket/3628#comment:3>
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