Subject: Re: [Boost-bugs] [Boost C++ Libraries] #2230: Wrapping Python function pointer
From: Boost C++ Libraries (noreply_at_[hidden])
Date: 2010-06-13 03:30:49
#2230: Wrapping Python function pointer
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Reporter: william.marie@⦠| Owner: dave
Type: Feature Requests | Status: closed
Milestone: Boost 1.37.0 | Component: Python
Version: Boost 1.36.0 | Severity: Optimization
Resolution: invalid | Keywords: function pointer
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Changes (by steven_watanabe):
* status: new => closed
* resolution: => invalid
Comment:
It isn't possible to convert a python function into a C function pointer,
because a function pointer has no state. The closest you can get is to
use the call operator of boost::python::object. See
http://www.boost.org/libs/python/doc/v2/callbacks.html.
-- Ticket URL: <https://svn.boost.org/trac/boost/ticket/2230#comment:1> Boost C++ Libraries <http://www.boost.org/> Boost provides free peer-reviewed portable C++ source libraries.
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