Subject: [Boost-bugs] [Boost C++ Libraries] #4969: transform_iterator won't work with non-const operator() call for function object
From: Boost C++ Libraries (noreply_at_[hidden])
Date: 2010-12-09 01:56:03
#4969: transform_iterator won't work with non-const operator() call for function
object
----------------------------------+-----------------------------------------
Reporter: zhuo.qiang@⦠| Owner: dave
Type: Bugs | Status: new
Milestone: To Be Determined | Component: iterator
Version: Boost 1.45.0 | Severity: Regression
Keywords: |
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transform_iterator declare it's copied function object as:
{{{#!c++
UnaryFunc m_f;
}}}
And it's dereference function as:
{{{#!c++
typename super_t::reference dereference() const
{ return m_f(*this->base()); }
}}}
which makes it impossible to cooperate with function object with non-const
operator() overloading, and and it will also make transformed adaptor in
boost::range not work:
{{{#!c++
struct Fun
{
typedef bool result_type;
bool operator()(int a)
{
return a != 1;
}
};
Fun f;
boost::find(all|boost::adaptors::transformed(f), true);
}}}
A boost::ref won't work here since the result has no result_type defined
And the only solution would be using a boost::function to hold the
original function object, however, doing so will give unnecessary run time
cost.
I suggest change the UnaryFunc m_f; definition to mutable, so that it will
work with non-const functor.
{{{#!c++
UnaryFunc mutable m_f;
}}}
-- Ticket URL: <https://svn.boost.org/trac/boost/ticket/4969> Boost C++ Libraries <http://www.boost.org/> Boost provides free peer-reviewed portable C++ source libraries.
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