From: Markus Schöpflin (markus.schoepflin_at_[hidden])
Date: 2002-12-06 05:21:08
I did send this message yesterday, but it seems to have vanished
somewhere along the way...
"David Abrahams" <dave_at_[hidden]> wrote in message
> lib a : a.cpp cool_lib/<shared>false : <shared>true
> <runtime-link>static ;
Let me try to rephrase this in plain words. Just tell me if I got it
You want to build a dynamic library (<shared>true) that uses the
static runtime model. And it links to cool_lib as a static library.
Did I get this right?
That leaves several questions:
1. How would I select the runtime model of cool_lib? Does is use the
same as lib a?
2. I'm assuming that you would get a static library a when you change
<shared>true to <shared>false. Is that correct?
3. If yes, what would I get if I don't say static or dynamic at all?
4. Is it really a good decision to drop the distinction between lib
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