From: Vladimir Prus (ghost_at_[hidden])
Date: 2005-05-26 03:33:59
On Thursday 26 May 2005 12:22, Malcolm Cifuentes wrote:
> Hi All,
> if I echo $(var) and receive this:
> I think it means I have 3 x file-target objects, is this correct?
It means there three instances of file-target class were created, and your var
is the name of the third instance.
> Is there any way I can iterate over each element/object?
Element of what? What are you trying to accomplish?
> I have tried a 'for in loop' which doesn't appear to work.
> for local t in $(var)
> echo "hi" ;
> I was hoping to see "hi" displayed times.
$(var) is a name of a single instance -- it's basically a list of lenth 1.
> given $(var).length returns 1 I am starting to think I've got it
What's $(var).length ? I don't think file-target class has any method by that
> [ $(var).str ] iterates over all 3 but I'm clueless if I can repeat
> how it does it.
The 'str' of file-target method prints the sources of the target, if any, and
does this with this code:
local action = [ action ] ;
local sources = [ $(action).sources ] ;
for local s in $(sources)
If you want to iterate over source, that's how to do it. If you want something
else, what's that? I don't understand why you'd want to iterate over all
instances of file-target ever created.
-- Vladimir Prus http://vladimir_prus.blogspot.com Boost.Build V2: http://boost.org/boost-build2
Boost-Build list run by bdawes at acm.org, david.abrahams at rcn.com, gregod at cs.rpi.edu, cpdaniel at pacbell.net, john at johnmaddock.co.uk