Re: [Boost-build] Excluding files from glob

From: Rene Rivera (grafik.list_at_[hidden])
Date: 2006-03-25 14:54:37

Vladimir Prus wrote:
> On Saturday 18 March 2006 20:54, Rene Rivera wrote:
>> Noel Belcourt wrote:
>>> Hi,
>>>
>>> We've got a couple of source directories that we depend on but cannot
>>> otherwise modify.  Our problem is that there are ~500 source files in
>>> this directory and I want to glob all the files but one.  Is there some
>>> notation to allow me to exclude one or more files from a glob?  I'd
>>> really hate to have to enumerate each source file in the Jamfile.
>> Assuming BBv2 for this example... Something like this should work:
>>
>> import set ;
>> import path ;
>>
>> local files =
>>    [ set.difference
>>      [ path.glob /path/ : *.cpp ] : [ path.glob /path/ : special.cpp ]
>>      ] ;
> 
> If this happen in Jamfile, things can be even simpler:
> 
>   import set ;
> 
>   local files =
>     [ set.difference
>      [ glob /path/*.cpp ] : /path/special.cpp ] ;
> 
> I.e.
>   - using 'glob' not 'path.glob' can be more convenient
>   - if there's one file to exclude, no need to glob for it, just name it

Just tried that... It doesn't work in a platform independent manner as 
you have to match the "/" vs "\" depending on the platform. But this works:

exe foo :
   [ set.difference
     [ glob /path/*.cpp ] : [ glob /path/special.cpp ]
     ] ;

As the glob will normalize both to the same style of path separators. 
And it's not like there's a worry about doing all that much extra work 
on the multiple globs, as directory scanning is cached within bjam.

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