Re: [Boost-build] Selecting a compiler on the commandline

From: Mark Van Peteghem (Mark.Van.Peteghem_at_[hidden])
Date: 2008-03-21 04:36:38

Vladimir Prus schreef:
> Mark Van Peteghem wrote:
>   
>> Hi,
>>
>> I have Visual C++ 6, VC++ 2003 and VC++ 2005 installed on my computer. I
>> downloaded boost_1_34_1 and the most recent version of bjam.
>>
>> I tried to build the regex library with the following batch file:
>>
>> set PATH=C:\Program Files (x86)\Microsoft Visual
>> Studio\VC98\Bin;C:\Libraries\boost-jam;c:\windows;c:\windows\system32;c:\windows\system
>> call vcvars32.bat
>> bjam --prefix=C:\Libraries\boost_1_34_1 -q -d+2 --with-regex
>> --toolset=msvc stage
>>
>> but it seems that it builds with the VC++ 2005 compiler: the libraries
>> and dlls have 80 in their name, and in the output of bjam I see that
>> VC++ 2005 is called with its complete path. How do I specify that I want
>> it to use VC++ 6?
>>
>> I find it very confusing that bjam is calling an application of which
>> you thought it couldn't find because it is not on the path.
>>
>>  From an earlier version of bjam I remember that you could specify
>> msvc-6_5 for the toolset, but when I try that now, I get errors about
>> /Ze and /Za options being incompatible.
>>     
>
> You can try --toolset=msvc-6.5
>   

This works, thanks!

I would like to suggest that this should be documented, I couldn't find 
it in the documentation (I remember it was for documented for the old 
version of bjam, and I found -6_5 in an old batch file). There are quiet 
some people who still use VC++ 2003, perhaps with VC++2005 installed as 
well, they need this as well.

Another suggestion is to stop with an error message if an unknown 
toolset is specified. Now it seems to look at the beginning (msvc in my 
example) if it doesn't recognize the whole expression (msvc-6_5 in my 
example), this is confusing.

-- 
  Mark
  _________________________________________
  When you get lemons, you make lemonade.
  When you get hardware, you make software.