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Boost-Build : |
Subject: Re: [Boost-build] make more than one target with one custom command
From: Roman Matsybora (matsic_at_[hidden])
Date: 2015-09-29 07:46:36
29 ÑенÑÑбÑÑ 2015, 14:33:52, Ð¾Ñ "Paulo Márcio Figueiredo Alves" < pauloalves1986_at_[hidden] >:
If you take a look at https://github.com/boostorg/build/blob/develop/example/generator/soap.jam  line 64 you will see an example on how to create two targets.
On Tue, Sep 29, 2015 at 5:42 AM Roman Matsybora < matsic_at_[hidden] > wrote:
I know all the files that will be produced. Can you provide example with 2 files generated and then sourced to exe?
--- ÐÑÑ
одное ÑообÑение ---
ÐÑ ÐºÐ¾Ð³Ð¾: "Steven Watanabe" < watanabesj_at_[hidden] >
ÐаÑа: 28 ÑенÑÑбÑÑ 2015, 20:29:57
AMDG
On 09/28/2015 11:02 AM, Roman Matsybora wrote:
> In Custom Command section of boost-build documentation there are 3 ways to use custom command: * using make rule
> * using notfile rule * using generate rule
> But all of these ways make only one target.
Actually generate can produce multiple
targets (as long as you know all the
files that will be produced). Just
create a list of all the targets and
return it from the generating rule.
> If project has some procedure that generates many source files at once, how can I declare them?
> Example:
> program make_sources creates a1.cpp and a2.cpp a1.cpp and a2.cpp are not available before build.
>
> main target is exe a : a1.cpp a2.cpp ;
> How to declare a1.cpp and a2.cpp targets?
>
In Christ,
Steven Watanabe
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