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Boost-Commit : |
Subject: [Boost-commit] svn:boost r75778 - trunk/libs/phoenix/doc/starter_kit
From: joel_at_[hidden]
Date: 2011-12-03 01:07:08
Author: djowel
Date: 2011-12-03 01:07:06 EST (Sat, 03 Dec 2011)
New Revision: 75778
URL: http://svn.boost.org/trac/boost/changeset/75778
Log:
fixes for comments from Dave Abrahams.
Text files modified:
trunk/libs/phoenix/doc/starter_kit/operator.qbk | 6 ++++++
trunk/libs/phoenix/doc/starter_kit/values.qbk | 9 +++++----
2 files changed, 11 insertions(+), 4 deletions(-)
Modified: trunk/libs/phoenix/doc/starter_kit/operator.qbk
==============================================================================
--- trunk/libs/phoenix/doc/starter_kit/operator.qbk (original)
+++ trunk/libs/phoenix/doc/starter_kit/operator.qbk 2011-12-03 01:07:06 EST (Sat, 03 Dec 2011)
@@ -40,6 +40,12 @@
x[ref(i)] // illegal (x is not a phoenix primitive or expression)
ref(x[ref(i)]) // illegal (x is not a phoenix primitive or expression)
+Why are the last two expression illegal? Although `operator[]` looks as
+much like a binary operator as `operator=` above it; the difference is
+that the former must be a member (i.e. `x` must have an `operator[]`
+that takes a phoenix primitive or expression as its argument). This will
+most likely not be the case.
+
[blurb __tip__ Learn more about operators [link phoenix.modules.operator here.]]
[heading First Practical Example]
Modified: trunk/libs/phoenix/doc/starter_kit/values.qbk
==============================================================================
--- trunk/libs/phoenix/doc/starter_kit/values.qbk (original)
+++ trunk/libs/phoenix/doc/starter_kit/values.qbk 2011-12-03 01:07:06 EST (Sat, 03 Dec 2011)
@@ -20,10 +20,11 @@
[heading Lazy Evaluation]
-Confused? `val(3)` is a unary function, you say? Yes it is. However, read
-carefully: /"evaluates to a nullary function"/. `val(3)` evaluates to (returns) a
-nullary function. Aha! `val(3)` returns a function! So, since `val(3)` returns a
-function, you can invoke it. Example:
+Confused? `val` is a unary function and `val(3)` invokes it, you say?
+Yes. However, read carefully: /"evaluates to a nullary function"/.
+`val(3)` evaluates to (returns) a nullary function. Aha! `val(3)`
+returns a function! So, since `val(3)` returns a function, you can
+invoke it. Example:
std::cout << val(3)() << std::endl;
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