Re: [Boost-Users] Why does lexical_cast make a copy?

From: Johan Ericsson (johanericsson_at_[hidden])
Date: 2002-03-22 19:09:10

--- "Daniel T." <daniel_t_at_[hidden]> wrote:
> I noticed that the function declaration of
> lexical_cast is:
> 
>      template<typename Target, typename Source>
> Target lexical_cast(Source arg)
> 
> Namely that arg is a copy of the original source. Is
> there a specific 
> reason that a copy is made? Why isn't it a 'const
> Source&' instead?
> 

I'll make a guess that it has to do with the double
reference problem. ie: the type of Source can be a
reference, so const Source& would be a double
reference...

Am I right?

Johan

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