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From: David Abrahams (dave_at_[hidden])
Date: 2004-03-31 08:19:26

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Anders Sundman <d00-asu_at_[hidden]> writes:

> (_1*_1)(_1 - _2) computes the (i1[i] - i2[i])^2 part

OK; I didn't know that's what you meant by "sum of squared
differences". I'd call that "the difference squared".

-- 
Dave Abrahams
Boost Consulting
www.boost-consulting.com

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