Re: [Boost-users] A simple question involving boost.function and boost.lambda

From: Wolfgang Meyer (Wolfgang.Meyer_at_[hidden])
Date: 2004-05-19 18:27:14

> I have tried:
> function0<void> funcs = (func1, func2);
> but this seems to execute only one of the two functions when it is called.

Here no lambda expression is involved. It is equivalent to "funcs = func2;".

> I have also tried:
> function0<void> funcs = (_1(), _2())(func1, func2);

Mhm, don't know whether this should work. However, the following
does:

function0<void> funcs = ( bind<void>(func1), bind<void>(func2) );

You just delay the call to the function objects, as you would do with a 
function.

Wolfgang Meyer