[Boost-users] address of member operator() function defined with member templates!

From: Paul Elliott (pelliott_at_[hidden])
Date: 2004-11-24 23:06:10

This may be an general C++ question but:
I want to take the address of a member function
that happens to be an operator() operator, which is
defined with member templates in apply.hpp:

--------------quote----
namespace boost
{

template<class R> struct apply
{
    typedef R result_type;

    template<class F> result_type operator()(F & f) const
    {
        return f();
    }

    template<class F, class A1> result_type operator()(F & f, A1 & a1) const
    {
        return f(a1);
    }

-------end quote.

I want to take the address of operator() for <int,int>
which is defined by the member template above.

----Quote---
  // want to work with functions of the form int f(int);
  typedef int P(int);

  boost::function<int (P)> f = 
    //    boost::bind(boost::apply<int>(),_1,5);
    // above works but instead try below!
    boost::bind(&boost::apply<int>::operator()<int,int>,5);
    // above line produces error.
----end quote

I get error message:
exabind.cpp:23: error: no matching function for call to `bind(<unknown type>, boost::apply<int>, int)'

How do I specify a pointer to the member operator() method
defined with member template parameters <int,int>  ?

I must be doing something wrong. My brain hurts.

-- 
Paul Elliott                       1(512)837-1096
pelliott_at_[hidden]                    PMB 181, 11900 Metric Blvd Suite J
http://www.io.com/~pelliott/pme/   Austin TX 78758-3117