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From: Oliver Kowalke (oliver.kowalke_at_[hidden])
Date: 2005-02-04 04:22:42
Hi,
is it possible to use boost::function as drop-in replacment for ordinary
function pointers - or are there some other solutions?
I can't get the code below to work.
thx and best regards,
Oliver
typedef void (*FunctionPointer) ( int);
void my_fun( int i)
{ std::cout << i << std::endl; }
class MyFun
{
public:
void operator()( int i)
{ std::cout << i << std::endl; }
};
class Test
{
public:
void f( FunctionPointer fp)
{ fp( 1); }
};
void main()
{
Test tst;
MyFun mf;
boost::function< void(int) > f;
f = boost::ref( mf);
// tst.f( my_fun); // works
tst.f( f); // ??? - doesn't compile
}
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