Re: [Boost-users] [bind / lambda] binding a factory funtion instead ofan value

From: Peter Dimov (pdimov_at_[hidden])
Date: 2005-06-22 18:29:10

Bertolt Mildner wrote:
> Lets say i need a functor of type
> 
> typedef boost::function1<Ret, Arg1> Functor;
> 
> and i have a function
> 
> Ret Foo(Arg1 a, Arg2 b);
> 
> Creating a Functor object is easy if i have a Arg2 object
> 
> Arg2 arg2;
> 
> Functor f(boost::bind<Ret>(&Foo, _1, arg2);
> 
> 
> But what if i want to create the Arg2 object in the functor when it is
> used?
> 
> Like i have a function
> 
> Arg2 CreateArg2();
> 
> and i don't want
> 
> Functor f(boost::bind<Ret>(&Foo, _1, CreateArg2());
> 
> but something like
> 
> Functor f(boost::bind<Ret>(&Foo, _1, &CreateArg2);
> 
> so that f(arg1) = Foo(arg1, CreateArg2());

bind( Foo, _1, bind( CreateArg2 ) ).